# How do you find the slope of the tangent line to the parabola y = x^2 + 3x at the point (-3, 0)?

Jul 8, 2015

For the slope-function you need the derivative.
(of course you have checked that $\left(- 3 , 0\right)$ is on the function!)

#### Explanation:

$y ' = 2 x + 3$

Now you fill in the $x$:

$y ' = 2 \cdot \left(- 3\right) + 3 = - 3$ is the slope at that point.