Question

How do you find the slope of the tangent line to the parabola `y = x^2 + 3x` at the point (-3, 0)?

Answer 1

For the slope-function you need the derivative.
(of course you have checked that `(-3,0)` is on the function!)

Explanation:

`y'=2x+3`

Now you fill in the `x`:

`y'=2*(-3)+3=-3` is the slope at that point.