# How do you find the slope of the tangent to the curve y = 3 + 4x^2 - 2x^3 where x = a?

y=3+4x^2−2x^3
$\frac{\mathrm{dy}}{\mathrm{dx}} = 8 x - 6 {x}^{2}$
So the slope of the tangent to the curve at $x = a$ is
$8 a - 6 {a}^{2}$