How do you find the value of #arctan(tan((5pi)/6))#? Trigonometry Inverse Trigonometric Functions Basic Inverse Trigonometric Functions 1 Answer MeneerNask Jul 2, 2015 It would be #(5pi)/6# as #arctan# and #tan# camcel out. Explanation: #Tan# answers the question: what ratio is there between the opposite and the adjoining side when the angle is #(5pi)/6# #Arctan# answers the opposite question: what angle belongs to a certain ratio of opposite and adjoining sides. #tan# and #arctan# are opposing operators, comparable to square and square root, or multiplication and division. They cancel out each other. Answer link Related questions What are the Basic Inverse Trigonometric Functions? How do you use inverse trig functions to find angles? How do you use inverse trigonometric functions to find the solutions of the equation that are in... How do you use inverse trig functions to solve equations? How do you evalute #sin^-1 (-sqrt(3)/2)#? How do you evalute #tan^-1 (-sqrt(3))#? How do you find the inverse of #f(x) = \frac{1}{x-5}# algebraically? How do you find the inverse of #f(x) = 5 sin^{-1}( frac{2}{x-3} )#? What is tan(arctan 10)? How do you find the #arcsin(sin((7pi)/6))#? See all questions in Basic Inverse Trigonometric Functions Impact of this question 3869 views around the world You can reuse this answer Creative Commons License