Question

How do you find the value of `sin^2(225^circ)`?

Answer 1

`sin^2 225^o=1/2`

Explanation:

As `sin(180+A)=-sinA`

`sin225^o=sin(180^o+45^o)=-sin45^o`

but `sin45^o=1/sqrt2` and hence `sin225^o=-1/sqrt2`

Hence, `sin^2 225^o=(-1/sqrt2)^2=1/2`