# How do you find the value of tan(arcsin(1/2))?

$- \frac{\sqrt{3}}{3} \mathmr{and} \frac{\sqrt{3}}{3}$
sin x = 1/2 --> arc $x = \frac{\pi}{6}$, and arc $x = \frac{5 \pi}{6}$
a. $x = \frac{\pi}{6} - \to \tan x = \frac{\sqrt{3}}{3}$
b. $x = \frac{5 \pi}{6} - \to \tan x = - \frac{\sqrt{3}}{3}$