How do you find the value that will produce the maximum value of the function g(x)=3(x-12)(x+3)?
The minimum is located at
Start by multiplying out.
We now must complete the square to find the minimum, which will be the y-coordinate of the vertex, or the lowest point of the function.
The vertex in the form
We need the y-coordinate of the vertex, which is
Hence, the minimum of the function
Hopefully this helps!