Question

How do you find the vector v with the given magnitude of 9 and in the same direction as `u=<2,5>`?

Answer 1

See below.

Explanation:

A vector a with given magnitude in the direction of b, is given by:

`(||a||*b)/||b||`

`||u||=sqrt((2)^2+(5)^2)=sqrt(29)`

`||v||=9`

`(9(2+5))/sqrt(29)`

`18/sqrt(29)hati+45/sqrt(29)hatj` or `((18/sqrt(29)),(45/sqrt(29)))`