# How do you find the vertex and axis of symmetry, and then graph the parabola given by: #f(x)= -4(x - 8)^2 + 3#?

##### 1 Answer

Dec 29, 2015

You have the right form (vertex form). All that you have left to do is learn what parts of the equation signify what.

#### Explanation:

In a quadratic function of form y = a

The vertex of a parabola is at (p, q). As for the axis of symmetry, the p value is 8, and in this function the q value is 3. So the vertex is at (8,3).

With this information, the x and y intercepts, and a few other points found by plugging in x values and solving for y, you will be able to graph this parabola. Your graph, if done properly, will look like the following:

graph{y = -4(x - 8)^2 + 3 [-20, 20, -10, 10]}