# How do you find the vertex and axis of symmetry for y = -x^2 - 10x?

##### 1 Answer
Aug 30, 2015

Vertex (-5,25)
Axis of symmetry x= -5

#### Explanation:

To find the vertex and the axis of symmetry, the equation has to be written so that x terms form a perfect square:

$y = - \left({x}^{2} + 10 x + 25\right) + 25$

=-${\left(x + 5\right)}^{2} + 25$

This gives the vertex as (-5,25) and the axis of symmetry x=-5.