How do you find the vertex and axis of symmetry of  f(x)= 3x^2 + 12x + 1?

Mar 19, 2016

This is a quadratic equation of a parabola (the squared term gives it away)

$y = a {x}^{2} + b x + c$

the vertex is located where $x = - \frac{b}{2 a}$

this occurs where $x = - \frac{12}{2 \times 3}$ or at $x = - 2$

substitute into the equation to figure out the y coordinate of the vertex.
The axis of symmetry is the vertical line passing through the vertex which is $x = - 2$