# How do you find the vertex and intercepts for # f(x) = -3x^2 + 5x + 5#?

##### 1 Answer

Vertex is at

#### Explanation:

graph{-3x^2+5x+5 [-20, 20, -10, 10]}

This is the equation of Parabola of General form ax^2+bx+c.

Here a=-3 ; b=5 ; c=5 we know the co-ordinate

Now to find Y-intercept putting x=0 we get y = 5 i.e The parabola cuts the Y axis at 5. To get X intercepts putting y=0 ; we get the equation as