# How do you find the vertex and intercepts for #f(x)= -x^2 + 6x + 3#?

##### 1 Answer

Jan 8, 2017

The vertex is

The intercepts are

#### Explanation:

The vertex is the highest point or lowest point of the equation,

we complete the squares

We rewrite

We compare this to

and the vertex is

The axis of symmetry is

To find the intercepts,

first,

Let

second,

Let

Therefore,

The points are

The points are

graph{(y-(-x^2+6x+3))((x-3)^2+(y-12)^2-0.01)(y-1000x+3000)=0 [-18.1, 17.93, -2.36, 15.67]}