How do you find the vertex and intercepts for #x^2 = -8y#?
Only one intercept and that is at the point
The vertex is at
A lot of step by step explanation given.
Multiply both sides by (-1). Makes
Divide both sides by 8
Compare to the standard form of
All of these
As this is negative the graph is of general shape
The part of the equation
But our equation is
So at this point we can sate that Vertex
And we have
As the graph has the y-axis is the axis of symmetry the y-intercept can only be at the vertex.