# How do you find the vertex and intercepts for #(x+3)^2=16(y-2)#?

##### 1 Answer

Vertex

y-intercpt

x-intercept

#### Explanation:

This is almost in 'completed square' form.

Sometimes called vertex form.

We need to get the

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Vertex

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This occurs at

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This occurs at

Square root both sides

You can take the square root of a negative number but the answer is in the realm of Complex Numbers. Consequently the graph does not cross the x-axis

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Foot Note: The

The vertex (which is a minimum value in this case) is above the x-axis. That alone tells you that there is no solution to