Question

How do you find the vertex and intercepts for `y = (1/8)(x – 5)^2 - 3`?

Answer 1

the vertex is at `(5,-3)`

Explanation:

Your quadratic equation is of the form `y=a (x-h)^2+k`
The vertex is at the point `(h,k)`

`y= 1/8 (x-5)^2 + (-3)`

the vertex is at `(5,-3)`
graph{1/8(x-5)^2-3 [-2.03, 14.67, -6.53, 1.814]}