# How do you find the vertex and intercepts for y = (1/8)(x – 5)^2 - 3?

Jun 10, 2016

the vertex is at $\left(5 , - 3\right)$

#### Explanation:

Your quadratic equation is of the form $y = a {\left(x - h\right)}^{2} + k$
The vertex is at the point $\left(h , k\right)$

$y = \frac{1}{8} {\left(x - 5\right)}^{2} + \left(- 3\right)$

the vertex is at $\left(5 , - 3\right)$
graph{1/8(x-5)^2-3 [-2.03, 14.67, -6.53, 1.814]}