Question

How do you find the vertex and intercepts for `y = (1/8)(x – 5)^2 - 3`?

Answer 1

y-intercept is `1/8 or .125` ; x -intercepts are `5+2sqrt6 or 9.9 and 5-2sqrt6or .1`

Explanation:

Here Vertex is `(5,-3)` y-intercept: putting x=0 ; `y=1/8*25-3=1/8`
To find x intercepts putting y=0 we get `1/8*(x-5)^2=3 or (x-5)^2=24`
`:. (x-5) = 2sqrt6 and (x-5)= - 2sqrt6 and x= 5+2sqrt6 and x= 5-2sqrt6` graph{1/8*(x-5)^2-3 [-20, 20, -10, 10]} [answer]