# How do you find the vertex and intercepts for #y=2x^2-7#?

##### 1 Answer

Feb 29, 2016

Its vertex is

Its Y- intercept is also

Its X-intercepts are

#### Explanation:

Given -

#y=y=2x^2-7#

We shall have it as

#y=2x^2+0x-7#

Vertex

#x=(-b)/(2a)=(-0)/2 xx 2=0/4=0#

At

#y=2(0)^2-7=7#

Its vertex is

Its Y- intercept is also

X intercept

At

#2x^2-7=0#

#x^2=7/2=3.5#

#x=+-sqrt(3.5#

#x=1.87#

#x=-1.87#

Its X-intercepts are