# How do you find the vertex and intercepts for y =3(x+10)^2 +6?

Jan 11, 2016

Vertex (-10, 6)

#### Explanation:

x-coordinate of vertex:
(x + 10) = 0 --> x = -10
y-coordinate of vertex: y = 6
To find y-intercept, make x = 0 --> y = 300 + 6 = 306
To find x-intercept, make y = 0 and solve the quadratic equation:
${\left(x + 10\right)}^{2} = - \frac{6}{3} = - 2$. There are no real roots (no x-intercepts). The
parabola opens upward and is completely above the x-axis, regardless of the values of x.