How do you find the vertex and intercepts for #y = -4(x + 3)^2 - 6#?
This equation is quadratic in Vertex Form.
Notice that if you expand the brackets you would have
As the coefficient of
Consider the content of the brackets. You have +3.
Multiply this by negative 1 and you have the vertex x-value
Substitute -3 for
And is of shape
so there is no intercepts on the x-axis
The y-axis intercept is when