# How do you find the vertex and intercepts for #y=x^2 -4#?

##### 1 Answer

I found:

1) y-intercept

2) x-intercepts

3) vertex at

#### Explanation:

Your function is a Quadratic and can be represented by a Parabola:

We first find the intercepts:

1) y-axis:

set

to get:

2) x-axis (if exists):

set

solve:

that gives you

so you have 2 intercepts on the

We now find the vertex:

The

where

in your case we have:

so that

the

Graphically we can "see" these points:

graph{x^2-4 [-10, 10, -5, 5]}