# How do you find the vertex and intercepts for #y = x^2 - 4x - 12#?

##### 1 Answer

Nov 24, 2015

Find vertex and intercepts of y = x^2 - 4x - 12

#### Explanation:

x-coordinate of vertex:

y-coordinate of vertex: y = y(2) = 4 - 8 - 12 = -16

To find y-intercept, make x = 0 --> y = -12

To find x-intercepts, make y = 0 and solve the quadratic equation:

Find 2 numbers knowing sum (4) and product (-12).

Factor pairs of (-12) --> (-2, 6). This sum is 4 = -b. Then the 2 x-intercepts (real roots) are: -2 and 6.