# How do you find the vertex and intercepts for #y=x^2+6#?

##### 1 Answer

vertex at

y-intercept at

there is no x-intercept

#### Explanation:

**vertex**

The general vertex form is

Re-writing the given:

with vertex at

**y-intercept**

The y-intercept is the value of

Setting

The y-intercept is at

**x-intercept**

The x-intercept is the value of

For the given equation

Therefore

graph{x^2+6 [-15.54, 12.94, -1.06, 13.18]}