How do you find the vertex and intercepts for y = x^2 - 8?
1 Answer
vertex =
y-intercept =
x-intercepts =
Explanation:
The general equation for a quadratic function in vertex form is:
y = a(x-h)^2+k
With this equation,
y=1(x-0)^2-8
The vertex of a quadratic equation in vertex form is
To find the y-intercept, substitute
y=x^2-8
y=(0)^2-8
y=(0)-8
y=-8
To find the x-intercept, substitute
y=x^2-8
0=x^2-8
8=x^2
x=+-sqrt(8)
x=2sqrt(2) or-2sqrt(2)
x=2.83 or-2.83
Here is a graph of the equation:
graph{y= x^2-8 [-12.78, 12.53, -11.14, 2.05]}
As you can see, the graph has a y-intercept of