# How do you find the vertex and the intercepts for #f(x) = 4x^2 - 16x +21#?

##### 1 Answer

Apr 29, 2016

Vertex (2, 5)

#### Explanation:

x-coordinate of vertex:

y-coordinate of vertex:

Vertex (2, 5)

To find y-intercept, make x = 0 --> y = 21

To find x-intercepts, make y = 0 and solve the quadratic equation:

Since D < 0, there are no real roots, no x-intercepts.

Since a > 0 the parabola opens upward and it is completely above the x-axis.