How do you find the vertex and the intercepts for #f(x) =x^2 + 3#?
1 Answer
Jun 20, 2018
Explanation:
#"for a quadratic in the form "y=x^2+c#
#"the vertex has coordinates "=(0,c)#
#"here "c=3#
#color(magenta)"vertex "=(0,3)#
#"to find the x-intercepts let y = 0"#
#x^2+3=0rArrx^2=-3#
#"this has no real solutions, hence no x-intercepts"#
graph{x^2+3 [-10, 10, -5, 5]}
