How do you find the vertex and the intercepts for #y= -x^2 -3#?
1 Answer
Jun 21, 2018
Explanation:
#"for a quadratic in the form "y=ax^2+c#
#"the vertex is "(0,c)#
#"here "c=-3#
#color(magenta)"vertex "=(0,-3)#
#"since "a<0" it is a maximum"#
#"for intercepts let y = 0"#
#-x^2-3=0rArrx^2=-3#
#"this has no real solutions hence no x-intercepts"#
graph{-x^2-3 [-10, 10, -5, 5]}
