How do you find the vertex and the intercepts for #y = x^2 - 6x + 11#?
y intercept (0,11)
does not cross the x axis
The constant is 11 so the y intercept is (0,11)
complete the square
so the x coordinate of the vertex is 3.
Put x=3 into the equation
So (3,2) is the vertex.
As it is a positive quadratic it is