# How do you find the vertex and the intercepts for y = (x - 3)^2 - 2?

Feb 12, 2017

Vertex (3, -2)

x-intercepts: $3 + \sqrt{2} \mathmr{and} 3 - \sqrt{2}$
y-intercept 7

#### Explanation:

The equation is in vertex form. Its vertex is already evident. It is (3, -2).

For x- intercept put y=0 and solve for x. X-intercepts would be $3 + \sqrt{2}$ and $3 - \sqrt{2}$

For y- intercept put x=0. It would be y= 7