How do you find the vertex, axis of symmetry and intercepts of #f(x)=3x^2+x-3#?
f(x) = 3x^2 + x - 3
x-coordinate of vertex, or axis of symmetry:
y-coordinate of vertex:
To find y-intercept, make x = 0 --> y = -3
To find x-intercepts, make y = 0 and solve the quadratic equation
There are 2 real roots, or two x-intercepts: