How do you find the vertex, focus and directrix of x^2 + 6y = 0?

1 Answer
Jul 19, 2016

Vertex is (0,0)

Focus is (0,-3/2)

Eqn. of Directrix is y=3/2, i.e., 2y-3=0

Explanation:

For the Parabola x^2=4by, Vertex is (0,0), Focus is (0,b) and

eqn. of Directrix is y=-b.

Here, 4b=-6 rArr b=-3/2

ence, the Vertex is (0,0)

Focus is (0,-3/2)

Eqn. of Directrix is y=3/2, i.e., 2y-3=0