How do you find the vertex, focus and directrix of $x^2 + 6y = 0$ ?

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Answer 1 · 2016-07-19T11:14:09

Vertex is $(0,0)$

Focus is $(0,-3/2)$

Eqn. of Directrix is $y=3/2, i.e., 2y-3=0$

For the Parabola $x^2=4by$ , Vertex is $(0,0)$ , Focus is $(0,b)$ and

eqn. of Directrix is $y=-b$ .

Here, $4b=-6 rArr b=-3/2$

ence, the Vertex is $(0,0)$

Focus is $(0,-3/2)$

Eqn. of Directrix is $y=3/2, i.e., 2y-3=0$

How do you find the vertex, focus and directrix of x^2 + 6y = 0 x^2 + 6y = 0?