# How do you find the vertex for #y=2x^2 +11x-6#?

##### 2 Answers

#### Explanation:

Vertex form:

Vertex #=(-h,k)

To put this in vertex form you must complete the square on the x terms which is a pain because 11 is not divisible by 2:

first isolate the terms with x:

in the form

now add

now solve fo c:

see what I mean about it being a pain, insert solution in function:

now complete the square:

vertex

graph{2x^2 +11x-6 [-20.33, 25.28, -25.08, -2.28]}

vertex

#### Explanation:

The x-coordinate of the vertex is given by the formula

The y-coordinate of vertex is the value of

Vertex