# How do you find the vertex for y = 2x^2 + 8x -3?

Apr 15, 2015

Your quadratic is in the form $y = a {x}^{2} + b x + c$ where:
$a = 2$
$b = 8$
$c = - 3$
The coordinates of the vertex are:
${x}_{v} = - \frac{b}{2 a}$
${y}_{v} = - \frac{\Delta}{4 a}$
Where $\Delta = {b}^{2} - 4 a c$