# How do you find the vertex for y=4/3x^(2)-8x+6?

It is point $\left(3 , - 6\right)$

#### Explanation:

This is a parabola . The vertex of a parabola is the point where the parabola crosses its axis of symmetry.

The vertex formula for a parabola is

$y = a \cdot {\left(x - h\right)}^{2} + k$ where $\left(h , k\right)$ is the vertex. Hence rewriting

the given parabola as

$y = \frac{4}{3} \cdot {\left(x - 3\right)}^{2} + \left(- 6\right)$

we see that the vertex is $\left(3 , - 6\right)$

graph{4/3*(x^2)-8x+6 [-20, 20, -10, 10]}