Question

How do you find the vertex of a parabola `f(x)=2x^2 -4x`?

Answer 1

Find vertex of `f(x) = 2x^2 - 4x`

Explanation:

X-coordinate of vertex: `x = (-b/2a) = 4/4 = 1`
y-coordinate of vertex: `y = f(1) = 2 - 4 = - 2`