Question

How do you find the vertex of a parabola `F(x) = 3x^2 + 18x + 9`?

Answer 1

`F(x) = 3x^2 + 18x + 9`

Explanation:

x-coordinate of vertex: `x = (-b/2a) = -18/6 = -3`

y-coordinate of vertex: `y = f(-3) = 27 - 54 + 9 = - 18`