# How do you find the vertex of a parabola f(x) = 3x^2 + 6x + 1?

Jul 4, 2015

$f \left(x\right) = 3 {x}^{2} + 6 x + 1$

#### Explanation:

x-coordinate of vertex: $x = \left(- \frac{b}{2 a}\right) = - \frac{6}{6} = - 1$

y-coordinate of vertex: y = f(-1) = 3 - 6 + 1 = - 2