# How do you find the vertex of a parabola f(x)=x^2-x-12?

Jul 6, 2015

$\left(\frac{1}{2} , \frac{- 49}{4}\right)$

#### Explanation:

Write f(x) as y= ${x}^{2} - x - 12 = {\left(x - \frac{1}{2}\right)}^{2} - \frac{49}{4}$

Vertex would be $\left(\frac{1}{2} , \frac{- 49}{4}\right)$