Question

How do you find the vertex of a parabola `y=1/2[x+4]^2+2`?

Answer 1

The vertex of `y=1/2[x+4]^2+2` is at `(-4,2)`

Explanation:

The general vertex form of a parabola is
`color(white)("XXXX")` `y=m(x-a)^2+b` with vertex at `(a,b)`

`y=1/2[x+4]^2+2`
cn be converted into the vertex form as `y=1/2[x-(-4)]^2+2`