# How do you find the vertex of a parabola  y=1/2[x+4]^2+2 ?

The vertex of $y = \frac{1}{2} {\left[x + 4\right]}^{2} + 2$ is at $\left(- 4 , 2\right)$
$\textcolor{w h i t e}{\text{XXXX}}$$y = m {\left(x - a\right)}^{2} + b$ with vertex at $\left(a , b\right)$
$y = \frac{1}{2} {\left[x + 4\right]}^{2} + 2$
cn be converted into the vertex form as $y = \frac{1}{2} {\left[x - \left(- 4\right)\right]}^{2} + 2$