Question

How do you find the vertex of a parabola `Y= 3(x-2)^2- 12`?

Answer 1

The vertex is at `color(red)((2,-12)`.

Explanation:

`Y = 3(x-2)^2-12`

The vertex form for the equation of a parabola is

`y = a(x-h)^2 + k`, where (`h, k`) is the vertex of the parabola.

By comparing the two equations, we see that `h = 2` and `k = -12`.

The vertex is at (`2,-12`).