# How do you find the vertex of a parabola y=x^2 + .6x - 11?

Jul 5, 2015

Vertex (0.3, -11.09)

#### Explanation:

Write the equation in vertex form by completing the square of terms containing x, as follows:

y= ${x}^{2} + .6 x + .09 - .09 - 11$

= ${\left(x - 0.3\right)}^{2} - 11.09$

The vertex is therefor (0.3, -11.09)