# How do you find the VERTEX of a parabola y=x^2+9x+8?

Your parabola is in the form $y = a {x}^{2} + b x + c$
$a = 1$
$b = 9$
$c = 8$
${x}_{v} = - \frac{b}{2 a} = - \frac{9}{2}$
${y}_{v} = - \frac{\Delta}{4 a} = - \frac{{b}^{2} - 4 a c}{4 a} = - \frac{49}{4}$