# How do you find the vertex of a parabola y= [x-4]^2?

Jun 28, 2015

Find vertex

#### Explanation:

Vertex: x = 4 --> y = f(4) = 0

Jun 28, 2015

The vertex is at $\left(4 , 0\right)$

#### Explanation:

$y = {\left[x - 4\right]}^{2}$
can be thought of as a variant of the vertex form for a parabolic equation:
$\textcolor{w h i t e}{\text{XXXX}}$$y = m {\left(x - a\right)}^{2} + b$ with a vertex at $\left(a , b\right)$

Since $y = {\left[x - 4\right]}^{2}$
is equivalent to $y = 1 {\left(x - 4\right)}^{2} + 0$

$\textcolor{w h i t e}{\text{XXXX}}$the vertex is at $\left(4 , 0\right)$