# How do you find the vertex of a parabola y= [x+8]^2?

Jul 8, 2015

The vertex of $y = {\left[x + 8\right]}^{2}$ is at $\left(- 8 , 0\right)$

#### Explanation:

Any parabolic equation of the form:
$\textcolor{w h i t e}{\text{XXXX}}$$y = m {\left(x - a\right)}^{2} + b$
is in vertex form with its vertex at $\left(a , b\right)$

$y = {\left(x + 8\right)}^{2}$
is equivalent to
$\textcolor{w h i t e}{\text{XXXX}}$$y = 1 {\left(x - \left(- 8\right)\right)}^{2} + 0$
which is an example of the vertex form
with the vertex as $\left(- 8 , 0\right)$