Question

How do you find the vertex of `f(x)=3(x+1)^2-2`?

Answer 1

`"vertex at "(-1,-2)`

Explanation:

The equation of a parabola in `color(blue)"vertex form"` is.

`color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))`
where (h ,k) is the vertex and a is a constant.

`f(x)=3(x+1)^2-2" is in this form"`

`"with "h=-1" and "k=-2`

`rArr"vertex "=(-1,-2)`
graph{3(x+1)^2-2 [-10, 10, -5, 5]}