# How do you find the vertex of f(x)=3(x-9)^2+4?

The vertex is $\left(9 , 4\right)$.
$f \left(x\right) = 3 {\left(x - 9\right)}^{2} + 4$ is in vertex form, which is $f \left(x\right) = a {\left(x - h\right)}^{2} + k$, where $h = 9 , \mathmr{and} k = 4$. The vertex is $\left(h , k\right)$, which is $\left(9 , 4\right)$.