Question

How do you find the vertex of `f(x) = 8 - (x + 2) ^2`?

Answer 1

Vertex at `(-2,8)`

Explanation:

Note the standard vertex form of a parabola is
`color(white)("XXX")f(x)=color(green)m(x-color(red)a)^2+color(blue)b` with vertex at `(color(red)a,color(blue)b)`

The given function: `f(x)=8-(x+2)^2`
an easily be re-arranged into standard vertex form as
`color(white)("XXX")f(x)=color(green)(""(-1))(x-color(red)(""(-2)))^2+color(blue)8` with vertex at `(color(red)(-2),color(blue)8)`