# How do you find the vertex of f(x) = 8 - (x + 2) ^2?

May 1, 2018

Vertex at $\left(- 2 , 8\right)$

#### Explanation:

Note the standard vertex form of a parabola is
$\textcolor{w h i t e}{\text{XXX}} f \left(x\right) = \textcolor{g r e e n}{m} {\left(x - \textcolor{red}{a}\right)}^{2} + \textcolor{b l u e}{b}$ with vertex at $\left(\textcolor{red}{a} , \textcolor{b l u e}{b}\right)$

The given function: $f \left(x\right) = 8 - {\left(x + 2\right)}^{2}$
an easily be re-arranged into standard vertex form as
color(white)("XXX")f(x)=color(green)(""(-1))(x-color(red)(""(-2)))^2+color(blue)8 with vertex at $\left(\textcolor{red}{- 2} , \textcolor{b l u e}{8}\right)$