Question

How do you find the vertex of `f(x)=(x-1)^2-1`?

Answer 1

`" vertex "=(1,-1)`

Explanation:

`"the equation of a parabola in "color(blue)"vertex form"` is.

`color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))`

`"where "(h,k)" are the coordinates of the vertex and a"`
`"is a multiplier"`

`f(x)=(x-1)^2-1" is in vertex form"`

`"with "h=1" and "k=-1`

`rArrcolor(magenta)"vertex "=(1,-1)`
graph{(y-x^2+2x)=0 [-10, 10, -5, 5]}