Question

How do you find the vertex of `f(x)=-(x+2)^2-1`?

Answer 1

`(-2,-1)`

Explanation:

`"the equation of a parabola in "color(blue)"vertex form"` is.

`color(red)bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|))`
where (h , k) are the coordinates of the vertex and a is a constant.

`f(x)=-(x+2)^2-1" is in this form"`

`"with " h=-2" and " k=-1`

`rArrcolor(magenta)"vertex "=(-2,-1)`
graph{-(x+2)^2-1 [-10, 10, -5, 5]}