# How do you find the vertex of f(x) = x^2 + 6x - 2?

The vertex is V=(-3;-11)
The coordinates of a vertex of a parabola $f \left(x\right) = a {x}^{2} + b x + c$ are given by:
V=(-b/(2a);(-Delta)/(4a))
But instead of calculating $\Delta$ you can also calculate $q$ as $f \left(p\right)$ i.e. substitute $p$ for $x$ in $f \left(x\right)$.