How do you find the vertex of #y= -2(x+3)(x-1)#?
1 Answer
May 15, 2018
Explanation:
#"the vertex lies on the axis of symmetry which is "#
#"positioned at the midpoint of the zeros"#
#"to find the zeros set "y=0#
#rArr-2(x+3)(x-1)=0#
#"equate each factor to zero and solve for "x#
#x+3=0rArrx=-3#
#x-1=0rArrx=1#
#x_"vertex"=(-3+1)/2=-1#
#"substitute this value into the equation for y"#
#y_"vertex"=-2(2)(-2)=8#
#rArrcolor(magenta)"vertex "=(-1,8)#
